y-3x+6y=12 7y=3x+12 y=3x/7 +12/7
6-3x+12=0 6+12-3x=0 18-3x=0 18=3x x=6
15
all you do is subtract the 3x from both sides and you get:y = -3x + 12
3x + 8 = 20 3x = 20 - 8 3x = 12 3x = 12/3 x = 4
19 (7 + 12 = 4x - 3x)
Treat the "greater than" sign as an equal sign, so subtract 3 from 12 and you get 9. Divide the 9 by three and you get 3. You should get x > 3.
3x plus -5 equal 7. so x is 4 so 3times 4 is 12-5 will equal 7.
They are two regions of the Cartesian plane with the straight line 3x + 4y = 12 defining their boundary. That line is not part of either region.
3x + 12 + 10x = 13x + 12
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
If this is algebra then; 3x plus 12x = 15x
3x+42=6x+12 42=6x-3x+12 42=3x+12 42-12=3x 30=3x 10=x
-3x + 10x = 7x3x + 3x = 6x
3x-4=12 Plus 4 both sides 3x-4+4=12+4 3x=16 divide 3 both sides 3x/3=16/3 x=16/3 x= 5.33
3x+12=x+48: 3x-x=-12+48 2x=36 x=18
3x + 12 = 42 3x = 30 x = 10