8.235
6,762 to 3 significant figures is: 6,760
That is correct.
Nothing
3 of them.
The accuracy of the answer is limited to the LEAST significant figures of the input. So if two measured quantities are multiplied or divided, one of which is accurate to only two significant figures, and other to six significant figures, the answer is only accurate to two significant figures. HOWEVER: use all the figures you have for the calculation, and then round your answer to two significant figures. Also, however, remember that if you are multiplying by an actual exact number, as in doubling, the significant figures of that 2 is unlimited, so the answer is only limited by the significant figures of the number you are doubling.
4.107
1.0947. This can be nicely rounded up to 1.1 as it is reasonably close.
which is the correct product of the significant figures 3.278 and 4.23.
4,566 to 3 significant figures is 4,570.
75.6 times 12.33 = 932.148 correct to 6 significant figures
0.081778 to two significant figures is 0.082
147.658 to two significant figures is 150.
776,890 in four significant figures is 776,900.
6,762 to 3 significant figures is: 6,760
That is correct.
Significant figures are very important when it comes to calculations. If the mass of an electron is 9.10939 x 10-31 then its significant figures are: 9 x 10^-31( correct 1 significant figure), 9.1 x 10^-31 kg ( correct to 2 significant figures), 9.11 x 10^-31 (correct to 3 significant figures), and 9.109 x 10^-31 (correct to 4 significant figures).
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.