I'm going to go with 172.
pages 1-9 = 9 digits
pages 10-99 = 180 digiits
leaves 219 digits
each page from 100 on = 3 digits
219 /3 = 73
99 pages plus 73 page = 172
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642
183 odd pages.
315
9 digits used for pages 1 to 9 (9 pages * 1 digit)180 digits used for pages 10 to 99 (90 pages * 2 digits)453 digits used for pages 100 to 250 (151 pages * 3 digits)Total = 9 + 180 + 453 = 642 digits used.(Of course a trick answer is 10 as there are only 10 possible different digits in decimal).
Pages 1 - 9 each have one digit, and so in total they use 9. Pages 10 - 99 each have two digits. There are 90 pages there, so we have now used 9 + (90 x 2) = 189 digits. Our book uses 264 - 189 = 75 digits more than this. That equates to 25 pages with three digits: pages 100 to 124 inclusive. So the book has 124 pages. Pages 1 - 9: 9 digits Pages 10 - 99: 180 digits. Pages 100 - 124: 75 digits. Total: 264 digits.