To calculate 4 times the sum of a number and 6, you would first find the sum of the number and 6, then multiply that sum by 4. Let's represent the number as 'x'. So, the sum of the number and 6 would be x + 6. Multiplying this sum by 4 gives you the expression 4(x + 6), which simplifies to 4x + 24.
5x + 6
54 (5 + 4) x 6 = 54
2x3=6+4=10 2.
6 divided by the sum of 4 times x and 5 times k is equal to 6 times the reciprocal of (4x + 5k).
The sum of 10 plus -6 is equal to 4. The equation would read 10+-6=4.
The number is 54. The sum of its digits is 5 + 4 = 9. 54/9 = 6.
It is the equation 9x + 6 = 4
4*(n + 1) = 6*n*3
5x + 6
It is the equation 6x + 2 = 4
10n = -30 n = -3
9x + 6 = 2 9x = -4 x = -4/9
The sum of three times a number and its square is 10 more than 6 times a number?
It could be: 6*(4+659)
54 (5 + 4) x 6 = 54
2x3=6+4=10 2.
6 divided by the sum of 4 times x and 5 times k is equal to 6 times the reciprocal of (4x + 5k).