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This shape is a right triangle, who's equation is: c2=a2+b2 In this example, c is decribed by the 50ft cable and either a or b is described by the 15 ft anchor point. So the equation becomes: 502=152+b2. Solve for b, you get sqrt(2275) which is approx 47.7 ft

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Q: 50ft cable is stretched from the top of an antenna to an anchor point on the ground 15ft from the base of the antenna how tall is the antenna?
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