Work in cents...
10D + 25Q = 675 and D = Q + 8
Substitute: 10(Q + 8) + 25Q = 675
ie 10Q + 80 + 25Q = 675
ie 35Q = 595
so Q = 17, making D = 25
He has 18 quarters (for $4.50)...........and 10 dimes ($1.00)
What kind of question is this exactly?
7 nickels, 4 dimes, 3 quarters
4 Qs 12 Dimes 20 Nickles
7 nickels, 4 dimes, and 3 quarters.
He has 18 quarters (for $4.50)...........and 10 dimes ($1.00)
What kind of question is this exactly?
Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?
Eighteen
7 nickels, 4 dimes, 3 quarters
4 Qs 12 Dimes 20 Nickles
7 nickels, 4 dimes, and 3 quarters.
This question cannot be answered.Assume there is1 nickel. There must be 3 more than that in quarters - that makes4 quarters and there are13 dimes---- that adds up to18
More than 25.
The question is incomplete. Please post a new version with the rest of the problem.
2 quarters, 4 dimes and 3 pennies.2 quarters, 4 dimes and 3 pennies.2 quarters, 4 dimes and 3 pennies.2 quarters, 4 dimes and 3 pennies.
To make a dollar using only quarters, dimes, and nickels with no more than one nickel and no more than nine dimes, we can set up a system of equations. Let q be the number of quarters, d be the number of dimes, and n be the number of nickels. We have the following constraints: 25q + 10d + 5n = 100 cents, 0 ≤ n ≤ 1, 0 ≤ d ≤ 9, and q + d + n ≤ 10. By solving these equations, we can find the number of ways to make a dollar under these conditions.