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∙ 14y agoThere are 78 girls in the school.
66+12=78
Wiki User
∙ 14y agoSuppose there are b boys in the school. Then there are 2*b girls. So there are 2b + b = 3b girls and boys 3b = 1500 so b = 500 and then 2b = 1000 So there are 500 boys and 1000 girls.
189 boys
1380 girls.
A ratio of boys to girls was 3 to 7 and there were 200 more girls than boys there would of been 150 boys that enrolled in school this year. This is a math problem.
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385 girls
Many all-boys schools have an affiliated nearby all-girls school. The girls from that school are often the cheerleaders for the boys' school teams.
Suppose there are b boys in the school. Then there are 2*b girls. So there are 2b + b = 3b girls and boys 3b = 1500 so b = 500 and then 2b = 1000 So there are 500 boys and 1000 girls.
depends on the school school event and how many girls and boys there are so if you are talking football games boys probally if its cheerleading more girls
190 girls
90 girls
189 boys
72 girls and 18 boys for a total of 90.
if there are only 8 MORE boys then girls then there are: 14 girls and 22 boysif there are 8 TIMES more boys than girls then there are: 32 boys and 4 girls
boys + girls = pupils → 40 + girls = 240 → girls = 240 - 40 = 200
153