A cube has 6 square faces, 12 edges and 8 vertices
A shape that has more faces than vertices is a polyhedron. In a polyhedron, the number of faces is always greater than or equal to the number of vertices. For example, a cube has 6 faces and 8 vertices, so it has more faces than vertices.
Since it has 9 faces it is a nonahedron. Not sure how many of the thousands of nonahedrons have 6 vertices.
It is a triangular prism that has 6 vertices, 9 edges and 5 faces.
A cube has 6 faces (all square faces), 8 vertices and 12 edges.
You are a cube that has 6 square faces, 12 edges and 8 vertices.
A cube
A cube has 6 square faces, 12 edges and 8 vertices
cube
None. A shape with four faces is a tetrahedron and that has 4 vertices, not 6.
square
It is not clear whether the question means the shape has ten faces of which 4 are square and 6 are not, or 6 faces of which 4 are square. In the first case the shape would be a 16-hedron. The second is impossible.
It is a cuboid that has 8 vertices, 12 edges and 6 faces
It is a cuboid that has 8 vertices, 12 edges and 6 faces
This shape is a cube.
That's an impossible shape. No shape can have only 2 edges.
A cube is a geometric shape which has 6 faces and 8 vertices ie .2 more vertices than faces