3y + 4z + 12y = 3y -3y -3y ------------------------- 4z + 12y = 0 divide everything by 4 z + 3y = 0 -3y -3y z = -3y
6x - 3y = 304x = 2 - y4x = 2 - yy = 2 - 4x (substitute 2 - 4x for y into the first equation)6x - 3y = 306x - 3(2 - 4x) = 306x - 6 + 12x = 3018x = 36x = 2y = 2 - 4x (substitute 2 for x)y = 2 - 4(2) = 2 - 8 = -6So the solution is x = 2, and y = -6.x + y = 2 + -6 = -4Thus, it is true that x + y = -4.
2x - 3y -7y + 4x - 5 = 6x - 10y - 5 and (6 x 10) - (10 x 4 ) - 5 = 60 - 40 - 5 = 15
x=5
3y + 2y + 4 + 1 = 805y + 5 = 805y = 75y = 15
Yes.
(x, y) = (3, 7) is a solution.
The question is not quite clear, do you mean -6x+3y = -18 and -10+5y = -30? If so then the solution is: -10+5y= -30 5y = -30+10 5y = -20 y = -4 Substitute the value of y into the equation -6x+3y = -18: Answer: x = 1 and y = -4
Inconsistent linear equations in two variables.
4.34684352143
6x - 3y + 2 = -3y - 2x8x + 2 = 0 (add 3x + 2y to both sides)8x = -2 (subtract 2 from both sides)x = -1/4 or -0.25 (divide both sides by 8)
Let's see if I can answer this. 4X + 6Y + 3Y + 4W + 6X - 7W = (4 + 6)X + (6 + 3)Y + (4 - 7)W = 10X + 9Y - 3W
4
6x+4=52 6x=48 x=8
-6x
2x-3y-7y+4x-5=6x-10y-5=6*10-10*4-5=60-40-5=60-45=15
4y + 4 = 3y - 5 y = -9