9C5 = 9!/[(9 - 5)!5!] = 9!/(4!5!) = (9 x 8 x 7 x 6 x 5!)/(5! x 4 x 3 x 2 x 1) = 3 x 7 = 21
5/7 x 4/9 = 20/63Multiply across: 5 x 4 = 20, and 7 x 9 = 63 giving the answer of 20/63
Start with the equation equaling 7; 3/4(X + 5) - 2 = 7 X + 5 = 4/3(7 + 2) = 4/3 x 9 = 12 X = 12 - 5 = 7
-99
If: x+(-5) = 4 Then: x = 9
9C5 = 9!/[(9 - 5)!5!] = 9!/(4!5!) = (9 x 8 x 7 x 6 x 5!)/(5! x 4 x 3 x 2 x 1) = 3 x 7 = 21
If the equation is (-9-7)x = -5, then x= .3125 or 5/16 If the equation is -9-7x = -5, then x = -.571428 or -4/7
5/7 x 4/9 = 20/63Multiply across: 5 x 4 = 20, and 7 x 9 = 63 giving the answer of 20/63
(2 x 3 x 4 x 5 x 6 x 7 x 8 x 9) + 1 will have a remainder of 1 when divided by 2, 3, 4, 5, 6, 7, 8, or 9. (2 x 3 x 4 x 5 x 6 x 7 x 8 x 9) + 1 = 362,881
x=4 y=5 9x+7y=?? Replace: 9(4)+7(5)= 71
-9-7x=-5 express first the equation in terms of x, where, 7x=-9+5 then, 7x=-4 thus, x=-4/7
28/5 x 7/4 28/5 (4) x 7/4 (5) 112/20 x 35/20 = 3920/400 3920/400 reduces to 9 4/5.
(21 + 7) x (9-4) - 16 (28) x (5) - 16 140 - 16 124
Start with the equation equaling 7; 3/4(X + 5) - 2 = 7 X + 5 = 4/3(7 + 2) = 4/3 x 9 = 12 X = 12 - 5 = 7
2√20 - 3√7 - 2√5 + 4√63 = 2√(4 x 5) - 3√7 - 2√5 + 4√(9 x 7) = 4√5 - 2√5 - 3√7 + 12√7 = 2√5 + 9√7
9 = 3 x 3 16 = 4 x 4 25 = 5 x 5 36 = 6 x 6 49 = 7 x 7
91/7 ÷ 64/5 = (9 x 7 +1)/7 ÷ (6 x 5 + 4)/5 = 64/7 ÷ 34/5 = 64/7 x 5/34 = 160/119 = (119 x 1 + 41)/119 =141/119