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I don't believe this is possible. The formula for an odd number is (2n+1) where n is any integer. So, for seven odd numbers added together... {a,b,c,d,e,f,g are the integers)

(2a +1) + (2b +1) + ... + (2g+1) = 2(a+b+c+d+e+f+g) + 7 = 2(h) + 7 h is an integer

2h + 7 must be an odd number, thus it can't equal 40

Q: 7 odd numbers equal 40

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It is not possible. The sum of 7 odd numbers must be odd while 50 is not odd.

I was able to get the number 30 by adding 4 odd numbers 3 + 7 + 5 + 15 = 30 But i can't add 5 odd numbers to get 30

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Never. When you dont add the same odd number and even number of times. For example: 5 + 3 (2 odd numbers; and even amount of odd numbers ) = 8 5 + 3 + 7 = 15 an odd amount of odd numbers 5 + 3 + 7 + 9 = 24 another even amount of odd numbers. But never if you use the only same number

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It is not possible. The sum of 7 odd numbers must be odd while 50 is not odd.

I was able to get the number 30 by adding 4 odd numbers 3 + 7 + 5 + 15 = 30 But i can't add 5 odd numbers to get 30