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Q: 8 times the sum of a number and 4 is 72 find the number?

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72.

The sum of three consecutive integers is -72

y = 3x+8 x + y = 72 x = 16 y = 56

71 + 72 + 73 = 216

It is: (5+4) times 8 = 72

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82 + 8 = 64 + 8 = 72

72 - 3 = 69, 69/3 = 23 which is the smaller number. 23 x 2 = 46, 46 + 3 = 49 which is the larger number

12 and 60 ============ a + b = 72 a = 5b replacing a by 5b in the first equation 5b + b = 72 6b = 72 b = 12 72 - 12 = 60

to find the ratio divide the diameter by half.

23+24+25 = 72

The sum of the positive whole-number factors of 30 is 72.

72.

The sum of three consecutive integers is -72

5184 because 72squared(72 times 72)= 5184

72+73+74 = 219.

104 and 72

The third number is the sum of the previous two.

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