Yes. By definition a multiple of 8 is any number that can be expressed as 8*n, where n is an integer. But 8n=4*(2*n), and 2*n is an integer, when n is an integer. Because 8n equals four times an integer, 8n is a multiple of 4.
2n-5 = 8n+7 Subtract 8n from both sides and add 5 to both sides:- -6n = 12 Divide both sides by -6 to find the value of n:- n = -2
5
N=72
8n + (5-n) + 13 = 7n + 18
8n = 160 n = 20
3 + 8n = -58n = -8n = -1
8n = 1 n = 1/8
n=10/7. i did this one mentally. but are you sure its 8n minus negative 4n or is it 8n minus 4n? 8n- -4n does not equal 8n-4n 8n- -4n is the same as 8n+4n
n=3
n = 1/2
n=77
n = 1/2
If 8N=32 then N=8And to get that divide 8 from both sides so 8 divided by 8 cancels out so that would be like 8N= 32( * this sign i will use for division) *8 *8 Then you have N = 8
n = (65 - 25)/8 ie 5
Yes. By definition a multiple of 8 is any number that can be expressed as 8*n, where n is an integer. But 8n=4*(2*n), and 2*n is an integer, when n is an integer. Because 8n equals four times an integer, 8n is a multiple of 4.
8n-2+4n = 66-5n 8n+4n+5n = 66+2 17n = 68 n = 4