2x + 5x = 35 7x = 35 x = 35/7 x = 5
2x + 5x = 35 7x = 35 divide each side by 7 x = 5
5x=2x+27 subtract 2x from both sides get get X on only 1 side of the equation. 5x-2x=2x-2x + 27 leaves you with 3x = 27 divide both sides by 3 3x/3 = 27/3 leaves you with x = 9 answer X=9
2x2 + 5x = x*(2x + 5)
1 x 35 3.5 x 10 5 x 7
2x + 5x = 35 7x = 35 x = 35/7 x = 5
2x + 5x = 357x = 35x = (35 / 7) = 5
2x + 5x = 35 7x = 35 divide each side by 7 x = 5
2x+5x=35 what is x? x= 5 substitution ... 2x5= 10 5x5= 25 10+25= 35
2x+5x=35 what is x? x= 5 substitution ... 2x5= 10 5x5= 25 10+25= 35
=> 2x + 5x = 35{collect x's}=> 7x = 35{divide both sides by 7}=> x = 35/7 = 5
2x+3x=35 5x=35 x=7
5x + x - 6x + 2x = 2x
5x=2x+27 subtract 2x from both sides get get X on only 1 side of the equation. 5x-2x=2x-2x + 27 leaves you with 3x = 27 divide both sides by 3 3x/3 = 27/3 leaves you with x = 9 answer X=9
2x+5x=35 2+5(x)=35 7(x)=35 7*(5)=35 35=35
If: x+9+5x = 21+2x Then: x = 3
6 + 2x = 5x + 9 , 6 - 9 = 5x - 2x , -3 = 3x , x = -1