9x-5x-2x = -4
2x = -4
x = -2
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x=1 2/3 How?: 2x-4+3 = 5x-6 2x-1 = 5x-6 2x-1+1 = 5x-6+1 2x = 5x-5 2x-5x = 5x-5x-5 -3x = -5 -3x/-3 = -5/-3 x = 5/3 x = 1 2/3
5x -6y=-30 5x-6y=30 (2x+3y) (2x-3y)=30 4x+6y=30 4x=30 x=30/4
2x = 11x + 4 Subtract 11x from both sides: -9x = 4 Divide both sides by -9: x = 4/(-9) = -0.444...
10x² - 9x + 2 = 10x² - 5x - 4x + 2 = 5x(2x - 1) - 2(2x - 1) = (5x - 2)(2x - 1). * (Note that -5 and -4 have a sum of -9; and that their product is +20, which is also the product of +10 and +2. That answers any question of how we knew to split the -9x into -5x and -4x, in the first step, above. This method will work whenever one factorises any factorisable quadratic expression; although I will not attempt here to explain the theory of why.) * The roots are 2/5 and ½. That is, 10x² - 9x + 2 = 0 exactly when, either, 5x - 2 = 0, or 2x - 1 = 0.
If there are no equals you can simplify this by collecting all the x values together and use the addition property of signed numbers. 2x+4x-5x+x=2x; 4+3=7. 2x+7 is the simplified statement.