Ax + by = ay + bx
ax - ay + by - bx = 0
a(x - y) + b(x - y) = 0
(a + b)(x - y) = 0
-----------------------------------------------------
Another contributor continued:
Great !
When I saw this question, I was about to say "No it doesn't. Not unless A=B."
But "Blackfireweb" developed a much more in-depth analysis. Unfortunately, there was a
small error in his algebra, in the third line, where he collects like terms from the second line.
Repeating Blackfireweb's work:
Ax + By = Ay + Bx
A(x - y) + B(y - x) = 0
A(x - y) - B(x - y) = 0
(A - B) (x - y) = 0
-- The equation can only be true for all (x, y) if ( A = B ).
-- Otherwise, it's only true at a point where ( x = y ).
What this really means is: Whatever numbers you pick for 'A' and 'B', if you write an equation
such as appears in the question and then massage it a bit, you always find that you have
the equation ( Y = X ), and you realize that we have all been making something complicated
out of something simple.
Notice that the "question" doesn't even ask any question. It just makes a statement.
To which we reply: "OK. That's the equation ( Y = X ). So what ?"
Chat with our AI personalities
Ax + B = Bx + C Ax - Bx = (C - B) x (A - B) = (C - B) x = (C - B) / (A - B)
Assuming the question is about chemical reactions (rather than mathematics where it is placed), it is a double displacement.
Ax + Bx + C is called an algebraic expression.
x2+bx+ax+ab = x2+ax+bx+ab = x(x+a)+b(x+a) = (x+a)(x+b)
x = -c/(a+b), provided a+b is not 0