50" and 10" 60 = 5x + x = 6x; x = 10
Suppose the shorter piece is x feet long. Then the longer piece is x+1 feet long. The total length of the two pieces is x + (x+1) = 2x+1 feet. So 2x+1 = 9 so 2x = 8 so x = 4' and then the other piece is 5'
A 102 centimmeter board is cut into two pieces so that one piece is five times as the other . How long is each piece
Oh, dude, you're testing my math skills now? Alright, let's see... Well, since 1 meter is 100 centimeters, 3 meters would be 300 centimeters. So, you can cut 10 pieces of 30cm lengths from a 3m length. Math can be fun, right?
If 104 yards of ribbon is cut into 14 equal length pieces, each piece will have length of 7.43 yards, to the justified number of significant digits.
piece a has a greater length than piece b (a>b)
x the length of the shorter piece 3·x the length of the longer piece x + 3·x the length of the whole board = 4·x = 76" x = 76" / 4 = 19.
Length of the longer piece is 5/9 of 27 feet. So, Length of longer piece = {5/(4+5)}x27 = {5/9}x27 = 15 feet.
Using algebra it works out that the lengths are 8.4 feet and 33.6 feet because 4*(8.4) = 33.6 and 8.4+33.6 = 42 feet
Write an equation and solve it. Call the length of the shorter piece "x", in this case, the longer piece is "3x". The sum of the two is equal to 116 inches.
There will be 300 pieces of steel cable if it is cut into 8-centimeter lengths. This calculation is done by converting the total length of 24 meters into centimeters (2400 cm) and then dividing by the length of each piece (8 cm).
There can be 5 pieces.
If a piece of wire was cut into 2 pieces in the ratio 7:8 and the shorter piece was 14cm, then the length of the longer piece will 16cm.
28=A+B+c b=2A c=4A subst. a=4 b=8 c=16
50" and 10" 60 = 5x + x = 6x; x = 10
A single piece of wood can be as long as the tallest tree. California Redwood. Something like 150 feet. Finger jointed can be any length. Common lengths go to 16 ft. 20 and 24 at some lumber yards.
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