The total EW distance is 8 - 2 = 6 km.
The total NS distance is 5 km
Therefore, total distance from the start is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) =7.8 km (approx).
The answer assumes that the boat is sufficiently far from the poles so that the various stages of its travel is along perpendicular lines.
The total EW distance is 8 - 2 = 6 km.
The total NS distance is 5 km
Therefore, total distance from the start is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) =7.8 km (approx).
The answer assumes that the boat is sufficiently far from the poles so that the various stages of its travel is along perpendicular lines.
The total EW distance is 8 - 2 = 6 km.
The total NS distance is 5 km
Therefore, total distance from the start is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) =7.8 km (approx).
The answer assumes that the boat is sufficiently far from the poles so that the various stages of its travel is along perpendicular lines.
The total EW distance is 8 - 2 = 6 km.
The total NS distance is 5 km
Therefore, total distance from the start is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) =7.8 km (approx).
The answer assumes that the boat is sufficiently far from the poles so that the various stages of its travel is along perpendicular lines.
The total EW distance is 8 - 2 = 6 km.
The total NS distance is 5 km
Therefore, total distance from the start is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) =7.8 km (approx).
The answer assumes that the boat is sufficiently far from the poles so that the various stages of its travel is along perpendicular lines.
1249 + 2987 + 66245 = 70481
he traveled to america then japan then he got in a boat and now he is with you! this is why you know copy of wiki cause they tell lies hope it helped you as much as it did me and btw add mee bruuu :) facebook will help!
The speed of the boat is 36 km/h. Going upstream: 3h x 36km/h = 108 km, minus (6x3 =18 km) = 90 km Going downstream: 2h x 36km/h = 72 km, plus (6x2 =12 km) = 90 km
Angle D = 36.8699(degrees) using tan D = b/a. Hope this helps.
Boat WRT land, downstream 10 + 8 = 18 KMH Boat WRT land, upstream 10 - 8 = 2 KMH Boat WRT water 10 KMH
hm
25 miles
25
25 miles
Magellan traveled by boat. Magellan traveled by boat.
A trick question! The boat is still quite close to the point where it dropped the anchor! ============================ The boat is approximately 25 miles from its starting point, and exactly zero miles from the point where the anchor was dropped.
25 miles.
This is where you apply the pythagorean theorem: d = √(152 + 202) ∴d = √(225 + 400) ∴d = √(625) ∴d = 25 So the boat is 15 miles from it's starting point
Newfoundland, Canada and the North of Greenland off Baffin Bay.
Your answer depends on your starting point.
Depends on your starting point
they traveled in a boat