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The total EW distance is 8 - 2 = 6 km.

The total NS distance is 5 km

Therefore, total distance from the start is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) =7.8 km (approx).

The answer assumes that the boat is sufficiently far from the poles so that the various stages of its travel is along perpendicular lines.

The total EW distance is 8 - 2 = 6 km.

The total NS distance is 5 km

Therefore, total distance from the start is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) =7.8 km (approx).

The answer assumes that the boat is sufficiently far from the poles so that the various stages of its travel is along perpendicular lines.

The total EW distance is 8 - 2 = 6 km.

The total NS distance is 5 km

Therefore, total distance from the start is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) =7.8 km (approx).

The answer assumes that the boat is sufficiently far from the poles so that the various stages of its travel is along perpendicular lines.

The total EW distance is 8 - 2 = 6 km.

The total NS distance is 5 km

Therefore, total distance from the start is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) =7.8 km (approx).

The answer assumes that the boat is sufficiently far from the poles so that the various stages of its travel is along perpendicular lines.

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10y ago

The total EW distance is 8 - 2 = 6 km.

The total NS distance is 5 km

Therefore, total distance from the start is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) =7.8 km (approx).

The answer assumes that the boat is sufficiently far from the poles so that the various stages of its travel is along perpendicular lines.

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Q: A boat traveled 8 km east 5 km north then 2km west. How far is the boat from its starting point?
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