48 students per bus times 65 buses = 3120 students
(48x65=3120)
-108
They'll need 9 buses. Buses #1 through #8 will be full. Bus #9 will have only 16 students on it.
-108
Assuming all buses carried the same amount of students, then it was 54. 54 x 6 + 7 = 331
237 ÷ 11 = 21 r 6 You can't leave 6 people behind, so an extra minibus is needed, making 22 needed.
-108
fff
No one caresn
They'll need 9 buses. Buses #1 through #8 will be full. Bus #9 will have only 16 students on it.
To find out how many students were in each bus, we first subtract the students who traveled in cars from the total number of students: 331 - 7 = 324 students. Then, we divide the remaining students by the number of buses to determine how many students were in each bus: 324 students / 6 buses = 54 students in each bus.
To determine how many buses are needed to carry 30 people when each bus can carry 7 people, you divide the total number of people by the capacity of each bus. This calculation is (30 \div 7 \approx 4.29). Since you can't have a fraction of a bus, you would need to round up to the next whole number, which means you would need 5 buses to accommodate all 30 people.
3 buses are needed for the fieldtrip, providing maximum capacity for 252 students.
approximately 23476 busses are required because America is full of fatasses
-108
Different double-decker buses can carry different numbers of passengers. If all the passengers were to be seated, you would need 13889 London red buses. Of course, a single double-decker bus, over its lifetime, will carry a million (or more) passengers.
Many students ride school buses to school every day.
Assuming all buses carried the same amount of students, then it was 54. 54 x 6 + 7 = 331