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What about this coardboard cube? What would you like to know? Its dimension

Q: A coardboard cube constructed to have the same volume as 1mole of hydrogen at STP?

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3.61g/L D=m/v

At standard temperature and pressure. This means that, more or less, there are 6.022 X 10^23 diatomic molecules of H2 in that much volume. ( the volume not being under more than standard pressure; 760mm/Hg ) In twice the volume about twice the molecules under STP.

In 1 mole of water, the total amount of oxygen is only 16g. But the amount of the same in 1mole of Hydrogen peroxide is 32g. So more oxygen is present in hydrogen peroxide than in water.

No. A liter is a volume measurement for fluids (liquids and gases). A mole is 6.022 x 1023 of anything. In gases at STP, 22.4L = 1mole.

10.0gCl*1 mole Cl*22.4Cl L/ 35.45g Cl* 1mole Cl=6.32L Cl

PV=nRT. So at ntp P=1bar. If n= 1mole. R= .082. T=273K. Then 1V=1.273 .082. v=22.44 l of gas

Ther answer is none! ammonium bromide is made from hydrogen bromide and ammonia NH3 + HBr = NH4Br i mole of each makes 1mole of ammonium salt.

Volume of block = 8cm3. The density of Al is 2.7 g/cm3 Density = mass/volume Mass=Density*Volume Mass= 21.6g 21.6g Al *(1mole/26.98g) = .8 moles Al .8moles*(6.022*1023atoms/mole) = 4.82*1023 atoms

The number of Avogadro is 6,022 140 857(74).10e23.

Let's see. 7.00 grams nitrogen (1 mole N/14.01 grams)(6.022 X 10^23/1 mole N) = 3.01 X 10^23 atoms of nitrogen 3.01 X 10^23 ( 1mole H/6.022 X 10^23)(1.008 grams/1 mole H) = 0.504 grams of hydrogen

54.94g Manganese = 1mole = 6.023 x 1023 atoms

H2S 63.1 g H2S * 1 mol H2S / 34.076 g H2S = 1.85 mol H2S