5/6
3/5
Number of different possible choices = 8 + 6 + 9 = 23Number of available successful choices (blue marbles) = 6Probability of success = 6/23 = 0.26087 = 26.087 %(rounded)
i think 6 out of 9 right? then you simplify to equal 1 out of 3.:)
With replacement, the odds of the second extraction do not change after the first, because of independence of the two extractions. Hence, the probability of extracting two reds is (3/5)*(3/5), the probability of two greens is (2/5)*(2/5) and that of one red and one green is 2*(3/5)*(2/5).
The sample space of an experiment would be the set of all possible outcomes. If you are reaching your hand into a bag and pulling out a marble at random, the outcomes will either be (red)(red)(yellow)(yellow)(yellow)(yellow)(yellow). This gives seven different options. This will obviously change each time a marble is removed or added.
3/5
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
There is a probability of 3 that it will be blue.
The probability of selecting a red marble is 3/9
probability of pulling out a purple marble = 20/85probability of NOT pulling out a purple marble = 1 - 20/85 = 65/85 = 13/17
There are 13 marbles in total. The order is specified.P(1st is white and the 2ndis purple) = (7/13)(6/12) = (7/13)(1/2) = 7/26.
1 in 52
80% chance, Or 40/50
The probability of picking a green marble from a box that only contains blue marbles is zero.
3/5 or .6
It is 0.2
5/12