A multiplicative inverse of 5 mod7 would be a number n ( not a unique one) such that 5n=1
Let's look at the possible numbers
5x1=5mode 7
5x2=10=3 mod 7
5x3=15=1 mod 7 THAT WILL DO IT
3 is the multiplicative inverse of 5 mod 7.
What about the others? 5x4=20, that is -1 mod 7 or 6
5x5=25 which is 4 mod 7
5x6=30 which is -5 or 2 mod 7
How did we know it existed? Because 7 is a prime. For every Prime number p and positive integer n, there exists a finite field with pn elements. This is an important theorem in abstract algebra. Since it is a field, it must have a multiplicative inverse. So the numbers mod 7 make up a field and hence have a multiplicative inverse.
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A multiplicative inverse is the same as a reciprocal. The multiplicative inverse of x is 1/x. So, the multiplicative inverse of 4 is 1/4; or 7 is 1/7 and of 0.2 is 1/0.2 = 5.
Multiplicative inverses are two numbers whose product is one.Another name for multiplicative inverse is reciprocal. The reciprocal of 2/3 is 3/2. 2/3 X 3/2 = 6/6 = 1. The multiplicative inverse of 7 is 1/7. 7 X 1/7 = 7/7 = 1.
Multiplicative inverse is the number that, when multiplied, results in 1, usually 1/# 1/sqrt7 is the inverse, so just rationalize the denominator sqrt7/7 = square root of 7 divided by 7
1/0.7 = 1.428571.. (recurring)
It is 7 over 2 or 3.5