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If it is Rx=0, it means you are reflecting your set of coordinates and reflect it across the x-axis when x=0. So it pretty much is saying reflect it over the y-axi
The image is at (6, 3).
Draw a perpendicular from a point to the line of reflection. Extend this [perpendicular] line so as to double its length. This point is the image of the original point. Repeat for all key points of the original shape and then join them together.
I assume you mean y= 3x/4? you could sub in x values, (1,2,3) into the equation to find the y coordinates, and then you'll know both the x and y coordinates... or you could just find one point, and then use the slope (3/4) to determine the next point... (3/4) means to find the next point, you go up by 3, and move over 4 unless you meant y^3/4x....
Yes. Suppose the point is P = (x, y). Its reflection, in the x-axis is Q = (x, -y) and then |PQ| = 2y.
If the coordinates of a point, before reflection, were (p, q) then after reflection, they will be (-p, q).
Example: if you have a point with the coordinates (2,4), a reflection over the y-axis will result in the point with coordinates (-2,4).
me no no
Reflecting the the x-axis (line y=0) leaves the x-coordinate unchanged and negates the y-coordinate: (x, y) -> (x, -y) For example: (1, 2) -> (1, -2) (3, -4) -> (3, 4)
5
If it is Rx=0, it means you are reflecting your set of coordinates and reflect it across the x-axis when x=0. So it pretty much is saying reflect it over the y-axi
Yes, it will.
Point with y = 0 do not move.
The image is at (6, 3).
Geometry reflection: a flip of a figure over a specific point or line Real life situation: mirror or reflecting pool.
The line of reflection. A reflection is a transformation that acts like a mirror: It swaps all pairs of points that are on exactly opposite sides of the line of reflection.
Your new coordinates would be -2,5.