The length of the hypotenuse, alone, is not sufficient to determine the area of a triangle.
There is not enough information to solve this. You need to know one other length od a side to solve this.
Using the quadratic equation formula and Pythagoras' theorem the length of the hypotenuse works out as 67.5 mm which is 6.75 cm
The area of any triangle is1/2 of (the length of the triangle's base) times (the triangle's height).
To get the area of an equilateral triangle, you just need to know the length of one side. Multiply the length of one side by the square root of three and then divide the product by four, and you will get the area of the triangle.
A right triangle with a hypotenuse of length 15 and a leg of length 8 has an area of: 50.75 units2
The length of the hypotenuse, alone, is not sufficient to determine the area of a triangle.
The area is approximately 71.2 units2
The area is approximately 56.09 units2
There is no right triangle on the right! (Ignore the length of the hypotenuse of a right triangle.) if you have the length of the two legs (base and the upright side): (base x upright) ÷ 2 = area of the right angle triangle.
The area is approximately 22.91 units2
56.089 square units.
The length of the hypotenuse of a right triangle whose legs measure 45 cm and 60 cm is: 75 cmThe area of the triangle is 1,350 cm2
The hypotenuse only is not sufficient to determine the area of a right triangle, unless the triangle is stated to be isosceles, or there is some other information that allows determination of the length of a side in addition to the hypotenuse. The area of a right triangle with a given hypotenuse only approaches zero as one of the two acute angles approaches zero degrees.
A right triangle with a hypotenuse of 10m and a base of 5m has an area of: 21.65m2
The area is 71.29 square units
third leg 5, area 30