Diameter = 6.6cm, so radius = 3.3cm
Circumference = 2 * pi * radius
Circle. = 20.735 cm
Now we multiply by the length.....
20.735 * 8.8 = 182.468 cm^2
Now we have the 1cm overlap, which technically is a rectangle of dimensions 1cm * 8.8cm i.e. 1 * 8.8cm = 8.8 cm^2
We just add this on.....
182.468 + 8.8 = 191.268 cm^2 or 191.27 cm^2 (to 2dp)
Wouldn't you add 1 not 8.8? Because the question says there is a 1 cm overlap.
191.27cm^2
A cylinder with a diameter of 1 foot and 3 feet high has a surface area of 11 square feet.
The volume of a cylinder 2 feet in diameter and 5 feet high is: 15.7 cubic feet.
The total surface of the base is 2206 square feet (approx). The area of the top, if there is any, will be the same. The area of the side walls is 1582 square feet (approx).
The volume of a cone 4 feet high with a base diameter of 13 feet is: 177 cubic feet.
Dimensions are 970mm high by 580mm diameter
A cylinder with a diameter of 1 foot and 3 feet high has a surface area of 11 square feet.
diameter X pi = circumference circumference X height = area
Strange p-gram to have a diameter! Area is 30 x 20 ie 600 cm2
Area = pi*502 = 7853.981634 or about 7854 square feet.
area of object = (1/3) pi * radius^2 = (1/3) (pi) * (0.6)^2 = 0.377 Find the diameter of this object (assuming it's a circle), and that's the answer: diameter = radius * 2 radius = square root (area / pi) diameter = 2 * square root (area / pi) diameter = 2 * (0.335) = 0.67
The volume of a cylinder that is 30mm in diameter and 700mm high is 494,800.84mm3
No, a smaller diameter wire has a higher resistance. The 0.01 mm wire will have 1/100 the cross-sectional area of the 0.1 mm diameter wire, therefore the resistance will be 100 times as high.
It is focused on the largest area of vision by being the most "zoomed out", so you are looking at a much greater area than the high power field of view.
The diameter is 8 feet, circumference 25.12, area 50.24
Low resistance.AnswerSince resistance is inversely proportional to the cross-sectional area of a conductor, increasing the diameter ('thickness') of a conductor will reduce its resistance.For example, doubling the diameter of a circular-section conductor will quadruple its cross-sectional area, and reduce its resistance by one quarter.
The volume of cylinder 1' high x 1' diameter is: 0.785 cubic feet.
the diameter of the high power field microscope is 500 micrometers