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The lateral surface area, L.A., of a regular pyramid is given by the formula,

L.A. = (1/2)nsl, where

n = number of the sides of the base
s = length of the each side of the base
l = slant height.

The surface area S.A. is given by the following formula.

S.A. = L.A. + B, where B is the area of the base.

In our problem,

n = 4
s = ?
l = 9 cm
L.A. = 270 cm2

So we have:

L.A. = (1/2)nsl
270 cm2 = (1/2)(4)(s)(9 cm)
270 cm = 18s
s = 270/18 cm
s = 15 cm

S.A. = L.A. + B
S.A. = = 270 cm2 + (15 cm)2
S.A. = 270 cm2 + 225 cm2
S.A. = 495 cm2

In the same way you will work to find the pentagonal base length side and the total area of a regular pyramid.

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Q: A square based pyramid has a lateral area of 270cm and a slant height of 9cm. How do you find the length of a side of the pentagonal base and the total area?
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