You can express that problem as an equation where x is the speed of the train:
300km ÷ x km/h = 300km ÷ (x + 5) km/h + 2h
Then solve the equation for x, recalling that you can treat the units of measurement just like any other variable, manipulating them as necessary:
∴ 300h / x = 300h / (x + 5) + 2h
∴ 300h / x = (300h + 2h[x + 5]) / (x + 5)
∴ 300h(x + 5) = x(300h + 2h[x + 5])
∴ 300hx + 1500h = 300hx + 2hx2 + 10hx
∴ 2hx2 + 10hx - 1500h = 0
∴ x2 + 5x - 750 = 0
∴ (x - 25)(x + 30) = 0
∴ x ∈ {25, -30}
So we know that the speed must have been either twenty-five, or negative thirty kilometers per hour. As the negative value makes no sense in this case, we know that the correct value is twenty five.
We can say then that the train was moving at twenty-five kilometers per hour.
A light year is a measure of distance, not time. A light year is the distance light travels in one year. In one day light travels 16,081,407,123 miles.
60km. 80*.75 = 60.00
43
53
That is incorrect. The distance travelled north cancels out the distance travelled south. Therefore - he only travels three blocks east.
1.35 minutes
If a car travels at a constant speed of 80m/s, then it covers the distance of 1,400m in exactly 17.5 seconds, no longer and no shorter. If the time is not 17.5 seconds, then either the distance was not 1,400m, or else the car's speed was not constant at 80m/s. Or both.
2.
9.8
The horizontal distance will be doubled.
rate times time = distance so 140
this can never change, light travels at a constant speed, a light year is the distance light travels in one year.
Assuming constant speed, you are supposed to divide the distance by the time.
cocomelin
Such an object is said to travel at a constant speed. If it doesn't change direction, it is also said to travel at constant velocity.
The formula for the distance traveled (assuming a constant speed) is:distance = time x speed So, any of the two factors on the right side of the equation will affect the distance.
one and a half times 20, ie 30 miles