0
01100111
01010011
=
10111110
Method : Same as in Decimal system, but highest possible number is 1.
Start at the last digits
1+1 = 0 and carry one
Second place is 1+1+the CarryBit 1 =1 and carry one.
Third place is 1+0+the CarryBit 1 = 0 and carry one.
Fourth place is 0+0+the CarryBit 1 = 1 and carry zero.
Fifth place is 0+1 and No CarryBit = 1 and carry zero.
Sixth place is 1+0 and No CarryBit =1 and carry zero.
Seventh place is 1+1 and No CarryBit = 0 and carry one.
Eighth place is 0+0 + the CarryBit 1 = 1 and carry none.
Cheers.
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Three of the following numbers add up to the number 31 17 3 2 19 5?
false none of the numbers add up to 31
What adds to 7 and multiples to 294?
There are no two real numbers that do, but two complex numbers do: (3.5 + i 3.5 √23) and (3.5 - i 3.5 √23) If you want them to add to 7 and multiply to -294, then the two real numbers -14 and 21 work. Or if you want them to add to -7 and multiply to -294, then the two real numbers 14 and -21 work. To add to -7 and multiply to 294, the following two complex numbers work: (-3.5 + i 3.5 √23) and (-3.5 - i 3.5 √23)
When using distributive property if you add the numbers is the answer a product or a sum?
If you simply add numbers the answer is the sum of those numbers.
What 2 numbers add to 25 and multiply to -54?
To find two numbers that add to 25 and multiply to -54, we can set up a system of equations. Let the numbers be x and y. We have the following equations: x + y = 25 and x * y = -54. By solving these equations simultaneously, we can find the two numbers. The numbers are 9 and -6, as 9 + (-6) = 3 and 9 * (-6) = -54.
What numbers do you add to get 11 and multiply to get 210?
221
Three of the following numbers add up to the number 31 17 3 2 19 5?
false none of the numbers add up to 31
What is the sum of the following numbers .03 .014 6 1.1?
Add them together to get the answer.
Three of the following numbers add up to the number 31 17 3 2 19 5.?
If you can only add some or all of the numbers together - you cannot achieve a total of 31. You can get the total 31 by the following... (19-2) + 17 - 3
write simple program to solve the following problems : add the following numbers = 10,222,99,999,74,532?
A+(B+C**3) (A-(+D+B/A+B)
What two factors of 7 add up to -30?
-23
What is all of the Fibonacci numbers in nature?
Its indefinite: Start with 0,1 add last two numbers = 1 add to sequence = 0,1,1 add last two numbers = 2 add to sequence = 0,1,1,2 add last two numbers = 3 add to sequence = 0,1,1,2,3 add last two numbers = 5 add to sequence = 0,1,1,2,3,5 add last two numbers ......... add to sequence ..........
The average of the following numbers: 1911, 1922, 1915, 1916, 1920?
Since we know that the average is calculated as the sum of all the data divided by the number of data, in this case we can add the numbers first and then divide the sum of the numbers by the number of data. The quotient is the average of these numbers_._
What is the mean of 8 and 24?
The answer is 16 The answer is 16, the mean is the same thing as the average (sum of the numbers divided by how many numbers you add) so following this you get... (8+24)/2=16.
How do you get the mean of a set of numbers?
add up all the numbers you have and then divide this result by how many numbers you have. example to find the mean of the following six numbers 6 7 9 3 3 2 first add up all the numbers = 6+7+9+3+3+2=30 then divide this result by how many numbers there are = 30 / 6 = 5 The mean is 5
What is the maean?
To find the mean of two or more numbers you add all the numbers together and divide by how ever many numbers there are.Example:find the mean of the following numbers: 25, 10, 13, & 4step 1: add the numbers together 25+10+13+4=52step 2: divide the answer by 4 because you were told to find the mean of 4 numbers 52/4=13step 3: the answer is 13
What is the formula for average?
you add all the numbers and divide by how many numbers there are by the answer you get when tou add all the numbers
What happens when you add 3 numbers together?
You can add 3 numbers (or any quantity of numbers) and get a sum.
