If A is number of adult tickets, and B is number of student tickets, we get a system of two equations for two unknowns:
4A+2B=2446
A+B=920
By solving this system, we obtain
B=617
No
1.818... % of the total marks.
If you make the assumption - without any justification - that all questions are worth the same, then each one is worth 1/35 of the total for the exam.
total clear weight is approx 570.00 today
11 ones, 2 twos
The tickets are $5 adult and $2 child. Here is the algebraic substitution. A = adult ticket money C = child ticket money 120C + 80A = 640 C = A-3 (three dollars less) 120 (A-3) + 80A = 640 120 A - 360 + 80A = 640 200 A = 1000 A = 5 C = A - 3 = 2 Checking your answer: 120(2) + 80 (5) = 240 + 400 = 640
Even though its usually hard as it is trying to get a scholarship as a high school student, its even harder as an adult. However, its not unrealistic and completely worth going for!
1,000 tickets
No misprinted instant tickets are not worth any money. The ticket will not be worth anything unless it has a winning match depending on the rules of the card.
$70.000
100
If one is interested in purchasing tickets for Radio City Spectacular events, it is worth visiting their official website as they do sell tickets there.
220 dollars divided by 10 dollars = 22. So Karen has sold 22 tickets. Add 22 tickets she sold to the 18 tickets she has left and you get________? This is the number of tickets she started with.
$937 million worth of tickets in the 2007-08 season.
yes
worth 1000 tickets
One Thousand