Linear Equation!
I am in advanced honors algebra and I just did homework with this question.
Select one equation from a system of linear equations. Select a second equation. Cross-multiply the equations by the coefficient of one of the variables and subtract one equation from the other. The resulting equation will have one fewer variable. Select another "second" equation and repeat the process for the same variable until you have gone through all the remaining equations. At the end of the process you will have one fewer equation in one fewer variable. That variable will have been eliminated from the system of equations. Repeat the whole process again with another variable, and then another until you are left with one equation in one variable. That, then, is the value of that variable. Substitute this value in one of the equations from the previous stage to find the value of a last variable to be eliminated. Work backwards to the first variable. Done! Unless: when you are down to one equation it is in more than one variable. In this case your system of equations does not have a unique solution. If there are n variables in your last equation then n-1 are free to take any value. These do not have to be from those in the last equation. or when you are down to one variable you have more than one equation. If the equations are equivalent (eg 2x = 5 and -4x = -10), you are OK. Otherwise your system of equations has no solution.
You first find a common denominator. The least common denominator is preferable but not essential. Multiply each term in the equation by this common denominator. The equation now has no fractions, only variables on both sides. If the resulting equation is linear, quadratic, cubic or exponential then there are relatively simple ways of solving them. There may be an analytical method for solving polynomials of higher order or other equations. However, whether or not there is a method will depend on the precise nature of the equation.
The idea is to replace one variable in the equation by the first number in the ordered pair, the other variable with the second number in the ordered pair, do the calculations, and see whether the resulting expressions are indeed equal.
you switch the numerator with the denominator then multiply the numerator first then the denominator.
Yes it is. Linear simply means that the degree (or number of powers) of the variable is 1. In this case the variable is the radius "r" and it occurs to the first power ... so the equation C=2 times pi times r is linear in r. Ralph the triangle
Neither variable appears anywhere in the equation in a denominator, or raised to any power except the first power.
Any variable in a linear equation is to the first power.The exponent is normally not written.
Yes, the equation 3x = 8y is a linear equation. A linear equation is an algebraic equation in which each term is either a constant or the product of a constant and a single variable raised to the first power. In this case, both 3x and 8y fit this definition, making it a linear equation.
you have to find a common denominator first, then you can just add them together and get your answer
A variable comes after the number 2n+5n=7n
Equations can be classified according to the highest power of the variable. Since the highest power of the variable in a linear equation is one, it is also called a first-order equation.
A linear equation is one in which the variable is raised to the first power (i.e. x, not x squared or x cubed or anything else). An example would be y = mx + c. In an exponetial equation the variable is part of the exponent, e.g. y = 3^x + c.
Written algebraically, the equation is (2/A)=4.The first step is to move the variable A from the denominator. To do this, multiply both sides of the equation by A:A*(2/A)=4*AThe A in the denominator on the left is canceled out and we are left with:2=4*ATo solve for A divide both sides of the equation by 4:2/4=ATwo over four simplifies to one half, which equals A:1/2=A
It does not matter.
(x,y) or (variable that cones first in the alphabet, variable that comes second in the alphabet)
Get rid of the denominator.
You write an equation that involves an independent variable (for example "x"), a dependent variable (for example "y"), and the first derivative, or higher-level derivatives, of the dependent variable (for example, dy/dx).