1, 2 and 4
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Let the unknown number be x: x-14+64 = 88 x = 88+14-64 x = 38 Check by substituting: 38-14+64 = 88
88
No. 88 is not evenly divisible by 12.
The numbers, in size order, are 56, 64 and 88. The middle number now is the median and that is 64.
88