Yes, they are.
Sketch of proof:
Odd square root is a number x of form x = 2n + 1.
Square of this root is:
x2=(2n+1)2=4n2+4n+1=y,
which can be expressed as:
y=2(2n2+2n)+1.
Let t = 2n2+2n.
Then,
y=2t+1, which is an odd number.
There are infinitely many of them. The square of every odd number will be an odd square number.
No, all perfect square numbers are not even numbers. Eg. the square of 3 is 9. (32=9) To generalize the proof: If p is odd then p=2n+1 and p2=(2n+1)2=4n2+4n+1=2(2n2+2n)+1 So odd numbers have odd square
Half of ALL numbers are odd. So half of those numbers are odd. Figure it out.
All the odd numbers between 1 and 2001.
If the numbers that are squared are odd, then the squared number will be odd. For example: 32 = 9 72 = 49 172 = 289 132 = 169 212 = 441 And all even numbers that are squared result in an even number. For example: 22 = 4 82 = 64 102 = 100 282 = 784 302 = 900
Half of all square numbers are odd. They are the ones which are the square of an odd number.
There are infinitely many of them. The square of every odd number will be an odd square number.
All square numbers have an odd number of factors.
yes 9 25 49 81 121 All odd numbers squared are odd numbers
Integers, odd integers, negative integers, odd negative integers, rational numbers, negative rational numbers, real numbers, negative real numbers, square roots of 1, etc.
All non-even numbers are odd. All squares of even numbers are even. All squares of odd numbers are odd. Therefore all numbers which are odd and not the square of an odd number are the solution set. It contains: {3, 5, 7, 11, 13, 15, 17, 19, 21, 23, 27, 29, 31, ...}
Yes.
Yes.
Square numbers have odd numbers of factors.
No, all perfect square numbers are not even numbers. Eg. the square of 3 is 9. (32=9) To generalize the proof: If p is odd then p=2n+1 and p2=(2n+1)2=4n2+4n+1=2(2n2+2n)+1 So odd numbers have odd square
No. Perfect square numbers have an odd number of factors.
The square of any odd number is also an odd number for reasons that should be obvious.