12
8 of the numbers less than 660 are divisible by 5 and 11 but not 3. All numbers divisible by 5 and 11 are multiples of their lcm; lcm(5, 11) = 55 All numbers divisibile by 5, 11 and 3 are multiples of their lcm; lcm(5, 11, 3) = 165 659 ÷ 55 = 11 54/55 → 11 numbers less than 660 are divisible by 5 and 11 659 ÷ 165 = 3 164/165 → 3 numbers less than 660 are divisible by 5, 11 and 3 → of the 11 numbers less than 660 divisible by 5 and 11, 3 are also divisible by 3 → 11 - 3 = 8 numbers less than 660 are divisible by 5 and 11 but not 3,.
Since all the numbers in that range start with "11", there is really only one option!
There are 9 palindromic numbers between 0 and 100: 11, 22, 33, 44, 55, 66, 77, 88 and 99.
Well, darling, those numbers all have something in common - they are all palindromic! That means they read the same forwards and backwards. So, whether you're reading them left to right or right to left, those numbers stay sassy and symmetrical.
Yes, there are many palindromic numbers that are not evenly divisible by 11 such as 181, 232, 454, 585, 10001, 17871, etc.
All of them are divisible by 1.
11
11
All odd numbers are not evenly divisible by 7. Try 11, for example.
-11
12
8 of the numbers less than 660 are divisible by 5 and 11 but not 3. All numbers divisible by 5 and 11 are multiples of their lcm; lcm(5, 11) = 55 All numbers divisibile by 5, 11 and 3 are multiples of their lcm; lcm(5, 11, 3) = 165 659 ÷ 55 = 11 54/55 → 11 numbers less than 660 are divisible by 5 and 11 659 ÷ 165 = 3 164/165 → 3 numbers less than 660 are divisible by 5, 11 and 3 → of the 11 numbers less than 660 divisible by 5 and 11, 3 are also divisible by 3 → 11 - 3 = 8 numbers less than 660 are divisible by 5 and 11 but not 3,.
Since all the numbers in that range start with "11", there is really only one option!
There are more 12-digit palindromic numbers than 11-digit palindromic numbers. This is because the number of possible 12-digit palindromic numbers is greater than the number of possible 11-digit palindromic numbers. In general, the number of palindromic numbers of length n is 9 * 10^((n-1)/2), so for 11-digit palindromic numbers, there are 9 * 10^5 = 900,000 possibilities, while for 12-digit palindromic numbers, there are 9 * 10^6 = 9,000,000 possibilities.
88 and all its multiples
There are 9 palindromic numbers between 0 and 100: 11, 22, 33, 44, 55, 66, 77, 88 and 99.