No - alternate multiples of 3 are odd, and alternate multiples are even.
50 is an even number so ALL its multiples are even...
I'm pretty sure it's a even number. even
All multiples of 6 are even numbers.
Even. Numbers ending in zero are multiples of 10, and 10 = 5 x 2, so all multiples of 10 are even.
The multiples of all odd numbers are odd and even. Odd x odd = odd. Odd x even = even. Since odd and even numbers alternate, the multiples will alternate as well.
Because not all odd numbers are multiples of 3 - I have shown you below that this is the case and you can see some multiples of 3 are even and some are odd and you can also see that there are even and odd numbers BETWEEN the multiples of 3. 1 (odd) 2 (even) 1*3 =3 (odd) 4 (even) 5 (odd) 2*3 = 6 (even) 7 (odd) 8 (even) 3*3 = 9 (odd) 10 (even) 11 (odd) 4*3 = 12 (even)
No - alternate multiples of 3 are odd, and alternate multiples are even.
No. 8 is an even number and all multiples of it must be even; 1217 is an odd number and so cannot be divisible by 8.
50 is an even number so ALL its multiples are even...
No, only every other multiple is odd. Example: 3,6,9,12,15,18
That happens because 5 is an odd number. An odd number times an odd number will give you an odd product; an odd number times an even number will give you an even product. The same happens for the multiples of any other odd number.
No number can satisfy these conditions: To have a remainder of 1 when divided by 6, the number must be odd (as all multiples of 6 are even and an even number plus 1 is odd) To have a remainder of 2 when divided by 8, the number must be even (as all multiples of 8 are even and an even number plus 2 is even) No number is both odd and even. → No number exists that has a remainder of 1 when divided by 6, and 2 when divided by 8.
All odd multiples of 3 are not factors of 8.
Multiples of 6 are even composite numbers.
The even integers are whole number multiples of 2. They include ...-8,-6,-4,-2,0,2,4,6,8,10,12,14,16,18,20... They include all numbers ending in 0,2,4,6 or 8. The other integers are odd integers. They are numbers that are not integer multiples of 2.
No. 217 is an odd number; 8 is an even number, all multiples of even numbers are even numbers. Thus 217 cannot be a multiple of 8 (or to put it another way: 217 is not divisible by 8).