Multiples of any even number will always stay even.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. The multiples of 8 are even.
No - alternate multiples of 3 are odd, and alternate multiples are even.
50 is an even number so ALL its multiples are even...
I'm pretty sure it's a even number. even
All multiples of 6 are even numbers.
Even. Numbers ending in zero are multiples of 10, and 10 = 5 x 2, so all multiples of 10 are even.
The multiples of all odd numbers are odd and even. Odd x odd = odd. Odd x even = even. Since odd and even numbers alternate, the multiples will alternate as well.
Because not all odd numbers are multiples of 3 - I have shown you below that this is the case and you can see some multiples of 3 are even and some are odd and you can also see that there are even and odd numbers BETWEEN the multiples of 3. 1 (odd) 2 (even) 1*3 =3 (odd) 4 (even) 5 (odd) 2*3 = 6 (even) 7 (odd) 8 (even) 3*3 = 9 (odd) 10 (even) 11 (odd) 4*3 = 12 (even)
No - alternate multiples of 3 are odd, and alternate multiples are even.
No. 8 is an even number and all multiples of it must be even; 1217 is an odd number and so cannot be divisible by 8.
No, multiples of 3 are not always odd numbers. A multiple of 3 can be either odd or even, depending on the specific multiple. For example, 3 and 9 are odd multiples of 3, while 6 and 12 are even multiples. Therefore, multiples of 3 include both odd and even numbers.
50 is an even number so ALL its multiples are even...
No, only every other multiple is odd. Example: 3,6,9,12,15,18
That happens because 5 is an odd number. An odd number times an odd number will give you an odd product; an odd number times an even number will give you an even product. The same happens for the multiples of any other odd number.
No number can satisfy these conditions: To have a remainder of 1 when divided by 6, the number must be odd (as all multiples of 6 are even and an even number plus 1 is odd) To have a remainder of 2 when divided by 8, the number must be even (as all multiples of 8 are even and an even number plus 2 is even) No number is both odd and even. → No number exists that has a remainder of 1 when divided by 6, and 2 when divided by 8.
All odd multiples of 3 are not factors of 8.
Multiples of 6 are even composite numbers.
The even integers are whole number multiples of 2. They include ...-8,-6,-4,-2,0,2,4,6,8,10,12,14,16,18,20... They include all numbers ending in 0,2,4,6 or 8. The other integers are odd integers. They are numbers that are not integer multiples of 2.