0
Area is 36x4-64x2 width is 6x2-8x what is the length in terms of x?
Wiki User
∙ 14y ago
Area 36x4-64x2 and width is 6x2-8x Area = Length * width
36x4 -64x2 = L * 6x2 -8x
(36x4 -64x2) / (6x2 -8x) = L
(36x4 -64x2) / (6x2 -8x) = L
((6x2 -8x)2 + 96x3)/ (6x2 -8x) = L
1 + 96x3/ (6x2 -8x) = L
1 + 96x3/ x(6x -8) = L
1 + 96x2/ (6x -8) = L
Wiki User
∙ 14y ago
Add your answer:
Earn +20 pts
What is the length and width of a rectangle that has a perimeter of 20 inches and an area of 24.4524 square inches showing work with final answers?
What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in
What is the perimeter of a table?
It is 2*(Length + Width).
A Has infinite length and length but no thickness?
A point has no length, width, or thickness. A line has infinite length but no width or thickness. A plane has infinite length and width but no thickness.
A rectangles width is 5 feet less than its length Write a quadratic function that expresses the rectangles area in terms of its length?
A(l)=l2-5l
The length of a rectangle is 3 inches more than its width and its perimeter is 22 inches Find the width of the rectangle?
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
What do you call the length of a side of a shape?
There are only three spacial terms and they are: length, width, and depth.
How does the length and width of a rectangle relate to the perimeter?
If you add the length and width together, it will always be half of the perimeter. In terms of an equation, it would look like so: Perimeter = (2 x Length) + (2 x Width)
What units would you use to measure the length of a wall?
Multiply the height by the width Area = length x width or (height x width in this case)
What is the length and width of a rectangle that has a perimeter of 20 inches and an area of 24.4524 square inches showing work with final answers?
What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in
How do define a square mile in terms of space?
One mile in length and one mile in width.
What are the dimensions of a table if the perimeter is 36 and the length is 5 times the width?
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
How do you you get the length if you have the area and the width?
Area = length x width Length = area/width
How many width are in a length?
Length / Width
Where is the length and width location?
Length and width
How do you find the length if you already have the width and the area?
If Length * Width = Area, then Area ÷ width = Length
What is the length and width of a whale?
The width can varies and is different for individuals of a species. In terms of length, is is 82 feet for largest species of whale on average. That would be a blue whale. They can measure upwards to 110 feet.
How do you find the length if the width and area is given?
Area = (length) times (width)Length = (area) divided by (width)Width = (area) divided by (length)
