Area 36x4-64x2 and width is 6x2-8x Area = Length * width
36x4 -64x2 = L * 6x2 -8x
(36x4 -64x2) / (6x2 -8x) = L
(36x4 -64x2) / (6x2 -8x) = L
((6x2 -8x)2 + 96x3)/ (6x2 -8x) = L
1 + 96x3/ (6x2 -8x) = L
1 + 96x3/ x(6x -8) = L
1 + 96x2/ (6x -8) = L
What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in
It is 2*(Length + Width).
A point has no length, width, or thickness. A line has infinite length but no width or thickness. A plane has infinite length and width but no thickness.
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
Perimeter = 2 lengths and 2 widths In your case length + width = 25cm If length is 5cm more than width then length = 15cm and width = 10cm
There are only three spacial terms and they are: length, width, and depth.
If you add the length and width together, it will always be half of the perimeter. In terms of an equation, it would look like so: Perimeter = (2 x Length) + (2 x Width)
The standard size of a piano key is typically around 6.5 inches in length and about 0.75 inches in width.
What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in
Multiply the height by the width Area = length x width or (height x width in this case)
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
One mile in length and one mile in width.
Area = length x width Length = area/width
Length and width
Length / Width
If Length * Width = Area, then Area ÷ width = Length
Area = (length) times (width)Length = (area) divided by (width)Width = (area) divided by (length)