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Arrange the numbers 1-10 in a circle in such a manner that the sum of any two adjacent numbers is equal to the sum of the two adjacent numbers diametrically opposite?
Wiki User
∙ 15y ago
11
Tyreek Hills
Wiki User
∙ 15y agoHere is my solution: 1, 7, 3, 9, 5, 6, 2, 8, 4, 10... wrapped around in a circle, of course. I saw no logical approach to this, but started out with the numbers simply arranged in order. Making two swaps (2 with 7, 4 with 9) was enough to produce a solution.
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