Assuming each letter in the following formula representss a unique digit - NOMAD x 4 Damon -what is the number represented by the digits Damon?

Answer 1

D = 8
A = 7
M = 9
O = 1
N = 2
This gives the following correct equation: 21978 x 4 = 87912 Getting to the answer by logic: The N in NOMAD has to be a small number: NOMAD x 4 must be less than 100000, otherwise DAMON wouldn't have five digits. N must be either 1 or 2, because 30000 x 4 has six digits. Next, we turn to the N in DAMON: it must be an even number: anything multiplied by 4 results in an even number. Therefore, N must be 2. Equation so far: 2OMAD x 4 = DAMO2 Since N is 2, the number represented by NOMAD must be between 20000 and 29999. Multiplying that by four, we see that DAMON must be between 80000 and 99999, so the D must be either an 8 or a 9. Also, the D in NOMAD multiplied by four, must end in a 2. Only 8 fits this criteria since 8 * 4 = 32, so D must be 8. Equation so far: 2OMA8 x 4 = 8AMO2 Next, we turn to the O in NOMAD. DAMON is a number between 80002 and 89992, so NOMAD must be a number between 20000 and 222498, so O must be 0, 1, or 2. Since N is already 2, O must be 0 or 1. Turning to the O in DAMON: if the O should be 0, there must be a number for A such that A8 x 4 ends in 02. Checking all possibilities for A does not yield a number that ends with 02, so O must be 1. Equation so far: 21MA8 x 4 = 8AM12 NOMAD is a number between 21008 and 21998, so DAMON must be between 84032 and 87992. Therefore, the A in DAMON must be 4, 5, 6, or 7. Also, A8 x 4 must be a number that ends with 12. The only number from 4-7 that fits is 7, since 78 x 4 = 312. Thus, A must be 7. Equation so far: 21M78 x 4 = 87M12 We have only one letter left: M. Just try all numbers from 0-9 and see that only 9 fits: M is 9. Final equation: 21978 x 4 = 87912.