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At which place in this series would you find the first seven 1 1 1 1 1 1 2 1 1 1 3 1 2 2 2 2 3 2 2 2?
Wiki User
∙ 13y ago
It is Mathematically impossible.
In order to find a single 7 in 1 1 1 1 2 1 1 1 3 1 2 2 2 2 3 2 2 2
The order would be as a requirement:
1 1 1 1 2 1 1 1 1 3 2 2 2 2 3 2 2 2 2 4 3 3 3 3 4 3 3 3 3 5 4 4 4 4 5 4 4 4 4 6 ---
--- 5 5 5 5 6 5 5 5 5 7 (THERE!)
If in that order the first 7 would be the 50th number. as from that you can see that the first 14 would be the 100th number, as well as the 21 being the 150th and so on.
Wiki User
∙ 13y ago
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To round 13.681 to once decimal place, you first need to look at the second decimal place and determine it's value. If the number is less than five, you will keep the number that is in the first decimal place. In this case, the number in the hundredths (second) position is an eight, which is greater than five. Therefore, we must change the six to a seven. The answer would be: 13.7
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