Because 1/3 are blue and 1/2 are red and the rest are green we can calculate that 1/6 of the marbles are green.
1/3 = 2/6
1/2 = 3/6
2/6 + 3/6 = 5/6 which leaves 1/6 green.
Since there are 7 green marbles we know there must be 7 x 6 total.
The answer is 42 marbles.
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10 Green marbles, 13 Blue marbles.
Let X = the number of green marbles. X+3 = the number of blue marbles. X + (X+3) = 23 2X + 3 = 23 2X = 20 X = 10 or the number of green marbles.
a+b=23 b=a+3 a+b a+(a+3)=23 a+a=23-3 2a=20 a=10 green marbles=10 blue marbles =23-10 =13
There are at least 11 green marbles in the bag.
hypergeom. f(1;13,3,1) * f(1;12,5,1)