/* This is an incomplete program. The function below will draw two parallel lines, but depends on a putpixel function that is not defined here. Also of course needs a main function calling it somewhere, and all the other usual necessities. */
/* draw a line from point (x1, y1) to point (x2, y2) and another one that is (xoffset, yoffset) pixels away from it. Uses Bresenham's line algorithm and depends on a "putpixel" function */
void pline(int x1, int y1, int x2, int y2, int xoffset, yoffset){
int n, deltax, deltay, sgndeltax, sgndeltay, deltaxabs, deltayabs, x, y, drawx, drawy;
deltax = x2 - x1;
deltay = y2 - y1;
deltaxabs = abs(deltax);
deltayabs = abs(deltay);
sgndeltax = sgn(deltax);
sgndeltay = sgn(deltay);
x = deltayabs >> 1;
y = deltaxabs >> 1;
drawx = x1;
drawy = y1;
putpixel(drawx, drawy);
putpixel(drawx + xoffset, drawy + yoffset);
if(deltaxabs >= deltayabs){
for(n = 0; n < deltaxabs; n++){
y += deltayabs;
if(y >= deltaxabs){
y -= deltaxabs;
drawy += sgndeltay;
}
drawx += sgndeltax;
putpixel(drawx, drawy);
putpixel(drawx + xoffset, drawy + yoffset);
}
}else{
for(n = 0; n < deltayabs; n++){
x += deltaxabs;
if(x >= deltayabs){
x -= deltayabs;
drawx += sgndeltax;
}
drawy += sgndeltay;
putpixel(drawx, drawy);
putpixel(drawx + xoffset, drawy + yoffset);
}
}
}
Chat with our AI personalities
supplementary angles on parallel lines.
Parallel lines are lines that never intersect or never cross and meet together. There is 4 letters in the alphabet that have parallel lines. E,F,H,I, and N. The letters A,X, and T are examples of intersecting lines. the lines meet together.
They are similar because they both have the definition of if A=B and B=C then A=C. They are different because since every parallel line is equal it shows that they do not exactly match up because of the transitive property of congruence.
The answer depends on what information you have and what form you are checking.The functional form of a parabola is y = ax2+ bx + c where a, b and c are real and a >0. If that is the case then, functionally it is a parabola.The graph of a parabola has a single turning point and is symmetric about its axis. But that is not enough. The graph of y = ax4+ bx2 + c or y = ax6+ bx3+ c have similar shapes but they are not parabolas.Find the axis. This should be easy because the parabola is symmetric about its axis. Draw a number of lines parallel to the axis. Where they meet the parabola, reflect them. These reflected lines should all meet at the same point which is the focus of the parabola.
You don't write an algorithm for a C++ program, unless you are documenting the C++ program after-the-fact. The normal procedure is to write the algorithm first, in a language independent fashion, and then translate that stated algorithm into C++ code, or into whatever language you wish.