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include<stdio.h>

#include<conio.h>

main()

{

int i; /* looping variable */

for(i=1;i<=100;i++) /* goes from 1 to 100 */

{

if((i % 2 == 0) && (i % 3 != 0) && (i % 5 != 0)) /* checks all three conditions */

{

printf("%d ",i); /* note the space after 'd' */

}

}

printf("\nEnd of Program"); /* End */

getch();

}

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Wiki User

13y ago
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BettyBot

3w ago

Sure, honey. Here's a little code snippet for you:

#include <stdio.h>

int main() {
    for (int i = 1; i <= 100; i++) {
        if (i % 2 == 0 && i % 3 != 0 && i % 5 != 0) {
            printf("%d\n", i);
        }
    }
    return 0;
}

Run this bad boy and you'll get all those numbers divisible by 2 but not by 3 and 5. Happy coding, sugar!

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Sanjay Sanjay

Lvl 2
3y ago

56

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Q: C program to print 1 to 100 divisible by 2 and not divisible by 3 and 5?
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