C program to print 1 to 100 divisible by 2 and not divisible by 3 and 5?

Answer 1

56

Answer 2

include<stdio.h>

#include<conio.h>

main()

{

int i; /* looping variable */

for(i=1;i<=100;i++) /* goes from 1 to 100 */

{

if((i % 2 == 0) && (i % 3 != 0) && (i % 5 != 0)) /* checks all three conditions */

{

printf("%d ",i); /* note the space after 'd' */

}

}

printf("\nEnd of Program"); /* End */

getch();

}

Answer 3

To achieve this in a C program, you can use a loop to iterate from 1 to 100. Within the loop, use an if statement to check if the number is divisible by 2 (num % 2 == 0) and not divisible by 3 (num % 3 != 0) and not divisible by 5 (num % 5 != 0). If the conditions are met, print the number. This will ensure that only numbers between 1 and 100 that are divisible by 2 but not by 3 and 5 are printed.

Answer 4

Sure, honey. Here's a little code snippet for you:

#include <stdio.h>

int main() {
    for (int i = 1; i <= 100; i++) {
        if (i % 2 == 0 && i % 3 != 0 && i % 5 != 0) {
            printf("%d\n", i);
        }
    }
    return 0;
}

Run this bad boy and you'll get all those numbers divisible by 2 but not by 3 and 5. Happy coding, sugar!

Answer 5

Oh, what a lovely request! In your C program, you can use a loop to go from 1 to 100. For each number, you can check if it's divisible by 2 using the modulo operator (%), and then check if it's not divisible by 3 and 5. If all conditions are met, you can print that number. Happy coding, my friend!