To calculate compound interest:
final_value = (1 + rate/100)periods x amount
So for amount = 2000, at a rate = 6% per year over a period of 35 years you get:
final_value = (1 + 6/100)35 x 2000
= 1.0635 x 2000
~= 15372.17
25000 x (1.02)14 = 32976.97. For comparison, compounded annually would give 25000 x (1.04)7 = 32898.29, not a huge difference but worth having!
Interest = 2472
11 years
If the interest is compounded annually, then the first interest payment isn't added until the end of the first year. Until then, the investment is worth exactly $15,000.00 .
Approx 44.225 % The exact value is 100*[3^(1/3) - 1] %
The future value of a 500 investment with a 5 annual interest rate compounded annually after 5 years is approximately 638.14.
25000 x (1.02)14 = 32976.97. For comparison, compounded annually would give 25000 x (1.04)7 = 32898.29, not a huge difference but worth having!
It might just be 10%.
It is 52936.72
8.0432 years (rounded) if compounded annually.
Interest = 2472
11 years
To calculate the future value of an investment compounded annually, you can use the formula: ( A = P(1 + r)^n ), where ( A ) is the amount of money accumulated after n years, ( P ) is the principal amount (initial investment), ( r ) is the annual interest rate, and ( n ) is the number of years. Here, ( P = 600 ), ( r = 0.065 ), and ( n = 3 ). Plugging in the values: ( A = 600(1 + 0.065)^3 ) Calculating this gives ( A \approx 600(1.207135) \approx 724.28 ). Therefore, the account will have approximately $724.28 after 3 years.
If the interest is compounded annually, then the first interest payment isn't added until the end of the first year. Until then, the investment is worth exactly $15,000.00 .
Assuming interest is compounded annually, 1000*(1.08)5
Approx 44.225 % The exact value is 100*[3^(1/3) - 1] %
Answer: 9.1% At 8.5% principal grows by (1+(.085/12))^12 = 1.0884 times in one year which is less than investing at 9.1%.