Multiply by the reciprocal:48 / (3/5) = 48 x 5/3.Next, simplify, dividing 48 and the 3 in the denominator by 3. The result is:18 x 5/1which is equal to 90.Multiply by the reciprocal:48 / (3/5) = 48 x 5/3.Next, simplify, dividing 48 and the 3 in the denominator by 3. The result is:18 x 5/1which is equal to 90.Multiply by the reciprocal:48 / (3/5) = 48 x 5/3.Next, simplify, dividing 48 and the 3 in the denominator by 3. The result is:18 x 5/1which is equal to 90.Multiply by the reciprocal:48 / (3/5) = 48 x 5/3.Next, simplify, dividing 48 and the 3 in the denominator by 3. The result is:18 x 5/1which is equal to 90.
5 feet is equal to 60 inches which is greater than 48 inches
2 7 6 9 5 1 4 3 8
33 desks can be arranged into six rows having no rows, 1 row, 2 rows, 3 rows, 4 rows, or 5 rows with exactly 5 desks.
It is simple, 15= 5 times 3 so you can write 5 problems in each 3 rows or 3 problems in each 5 rows. Hope I answered your math question correctly!
Draw either 3 rows of 5 columns or 5 rows of 3 columns.
43 + 5
Idk but i think you put them in 5 rows of 6 cause 6 times 5 = 30
Multiply by the reciprocal:48 / (3/5) = 48 x 5/3.Next, simplify, dividing 48 and the 3 in the denominator by 3. The result is:18 x 5/1which is equal to 90.Multiply by the reciprocal:48 / (3/5) = 48 x 5/3.Next, simplify, dividing 48 and the 3 in the denominator by 3. The result is:18 x 5/1which is equal to 90.Multiply by the reciprocal:48 / (3/5) = 48 x 5/3.Next, simplify, dividing 48 and the 3 in the denominator by 3. The result is:18 x 5/1which is equal to 90.Multiply by the reciprocal:48 / (3/5) = 48 x 5/3.Next, simplify, dividing 48 and the 3 in the denominator by 3. The result is:18 x 5/1which is equal to 90.
37
5 feet is equal to 60 inches which is greater than 48 inches
2 7 6 9 5 1 4 3 8
1 row of 180 - 2 rows of 90 - 3 rows of 60 - 4 rows of 45 - 5 rows of 36 - 6 rows of 30 - 9 rows of 20 - 10 rows of 18 - 12 rows of 15 - 15 rows of 12 - 18 rows of 10 - 20 rows of 9 - 30 rows of 6 - 36 rows of 5 - 45 rows of 4 - 60 rows of 3 - 90 rows of 2 - 180 rows of 1 - total of 18 ways within the limits of the question
5 decades
33 desks can be arranged into six rows having no rows, 1 row, 2 rows, 3 rows, 4 rows, or 5 rows with exactly 5 desks.
It is simple, 15= 5 times 3 so you can write 5 problems in each 3 rows or 3 problems in each 5 rows. Hope I answered your math question correctly!
43 + 5