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Yes. 1 kg : 1 metre.

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Q: Can 54 kg and 54 m be expressed as a ratio?
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If you divide a force measured in newtons by a speed expressed in meters per second in what units will the answer be expressed?

1 newton = 1 kg-m/s2[Speed] = [m/sec]Force/speed = (kg-m/sec2) / (m/sec) = (kg - m - sec / sec2 - m) = kg/secThis quantity has little if any physical significance,which is probably why it's a unit without a name.


One Newton is expressed in?

A newton is a unit of force


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A newton is the unit of force in the metric system. In the formula F = m*a, the force F will be expressed in newtons if the mass & acceleration are expressed in kg & m/s².


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Proton Mass, m = 1.67x10-27 kg Proton Charge, q = 1.6x10-19 C m/q = 1.04x10-8 kg C-1


What unit is kinetic energy expressed in?

energy is express in units due to the explanation below :E = kg * m2/dt2 (kg* m/dt2) * mN * mWhat is this im confused?? what is this suppost to mean??


What are the units for the slope of a velocity-time graph?

Force, in Newtons, can be expressed as Kg*m/s2. Acceleration can be expressed as m/s2. If you divide it out, you get:= N / (m/s2)


How do you convert density to metric?

In physics the density (ρ) of a body is the ratio of its mass (m) to its volume (V), a measure of how tightly the matter within it is packed together. Its SI units are kilograms per cubic metre (kg/m³). Conversion to old measures. 1 kg/m³ equals 0.062428 lb/ft³ or 1 lb/ft³ equals 16.0184634 kg/m³.


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Mass is commonly expressed in kg, g, slugs, and in lbm.Weight is commonly expressed in Newtons or lbf.W = ( m ) ( g )Mass in kg and g in m per s^2 yield weight in Newtons.


Formula for molality?

== Molality== (1000xMolarity)/((1000xdensity of solution)- (MolarityxMolecular weight of Solute)) ==


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54 m = 0.054 kmTo convert from m to km, divide by 1000.


What volume is 54 g of aluminum if the density is 2.7gcm3?

You are dealing with density, so the formula is:D = m/vDensity = Mass ÷ VolumeIn the problem, you are given mass (54 g) and density (2.70 g/cm3); so we solve for v (volume).2.7 = 54 ÷ vv = 20 cm3


What is the size and direction of the final velocity of the tow cars if a 0.4 kg toy train car moving forward t 3 ms collides with and sticks to 0.8 kg toy car that is traveling in the opposite way?

0.4 kg(3 m/s) + 0.8kg(-2 m/s) = 1.2 kg m/s -1.6 kg m/s = -0.4 kg m/s -0.4 kg m/s = 1.2 kg(v) = (-0.4 kg m/s)/(1.2 kg) = v = -0.33 m/s the cars are traveling at 0.33 m/s in the direction of the second car.