6x2+5x+1 = (3x+1)(2x+1) when factored
2x + 5x = 35 7x = 35 x = 35/7 x = 5
2x2 + 5x = x*(2x + 5)
1
2x + 5x = 35 7x = 35 divide each side by 7 x = 5
6x2 + 5x - 6 is factored out to (2x + 3)(3x - 2).
2x2+5x+3 = (2x+3)(x+1) when factored
x2 + 5x - 120 can not be factored.
6x2+5x+1 = (3x+1)(2x+1) when factored
5x + 70 = 5 (x + 14)
It is: (5x-1)(5x+1) = 0 when factored
5x**2+6x+7 Multiply first and third coefficients 5*7=35 Factor result 5*7 1*35 None of these pairs adds up to the second term, cannot be factored
35x - 21 We note that '35' & '21' are both multiples of '7' ; (7 x 5 = 35 & 7 x 3 = 21). So seven is factored out. 7(5x - 3)
2x + 5x = 35 7x = 35 x = 35/7 x = 5
X(5-8)
15
No solution.