Yes, but only in exceptional circumstances.
An arithmetic mean is the sum of all the values in a set divided by the number of values in a set.
So the set could be, for example : (7, 13, 17, 20) and the arithmetic mean is thus 57/4 = 14.25.
If the answer is required as an integer then we would write 14.
The value 0.25 is effectively a remainder.
The same procudure could also apply to geometric and harmonic means.
Yes the mean can have a remainder but the remainder would normally be either rounded or converted into a fraction.
You incorporate the fractional remainder into the mean. The mean does not have to be a whole number.
If you mean 60 divided by 12 then it is exactly 5 with no remainder.
It means 4 can divide into it evenly with no remainder.
0.0328
Yes the mean can have a remainder but the remainder would normally be either rounded or converted into a fraction.
You incorporate the fractional remainder into the mean. The mean does not have to be a whole number.
0.12
Done the calculation (get the answer) and also show the remainder (don't round up or down).
a group or part that are left
U round it up
If you mean 60 divided by 12 then it is exactly 5 with no remainder.
It means what's left over after a division as for example 18/5 = 3 with a remainder of 3
If you mean evenly (with no fraction or decimal part or remainder) the answer is no. When it's divided by 36, the remainder is 18.
Do you mean what, when divided by 2, leaves a remainder? That'd be any odd number (or fraction).
The mean can be an improper fraction but it cannot have a remainder.
It means the remainder if any when numbers are divided as for example 49 divided by 6 = 8 with a remainder of 1 leftover