Let R1 = rational number Let X = irrational number Assume R1 + X = (some rational number) We add -R1 to both sides, and we get: -R1 + x = (some irrational number) + (-R1), thus X = (SIR) + (-R1), which implies that X, an irrational number, is the sum of two rational numbers, which is a contradiction. Thus, the sum of a rational number and an irrational number is always irrational. (Proof by contradiction)
It is a rational number.
If an irrational number is added to, (or multiplied by) a rational number, the result will always be an irrational number.
When a rational numbers is divided by an irrational number, the answer is irrational for every non-zero rational number.
Can be irrational or rational.1 [rational] * sqrt(2) [irrational] = sqrt(2) [irrational]0 [rational] * sqrt(2) [irrational] = 0 [rational]
Any, and every, irrational number will do.
They are rational and irrational
10.01 is a rational number
It is a rational number because it is a terminating decimal number which can also be expressed as a fraction
Let R1 = rational number Let X = irrational number Assume R1 + X = (some rational number) We add -R1 to both sides, and we get: -R1 + x = (some irrational number) + (-R1), thus X = (SIR) + (-R1), which implies that X, an irrational number, is the sum of two rational numbers, which is a contradiction. Thus, the sum of a rational number and an irrational number is always irrational. (Proof by contradiction)
Rational
The area of a triangle can be a rational number or an irrational number depending on its dimensions.
It is a rational number.
is 34.54 and irrational or rational. number
it is a rational number but 4.121314..... is an irrational no
Irrational.
Such a product is always irrational - unless the rational number happens to be zero.