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For the expression:

(√2 + √6) / (√8 + √6)

You can divide all terms by √2:

= (1 + √3) / (√4 + √3)

And solve the √4 in the denominator:

= (1 + √3) / (2 + √3)

You can then eliminate the radical in the denominator by using the "difference of squares", multiplying both the numerator and denominator by 2 - √3:

= (1 + √3)(2 - √3) / (2 + √3)(2 - √3)

= (2 - √3 + 2√3 - 3) / (4 - 3)

And simplify:

= (-1 + √3) / 1

= √3 - 1

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13y ago

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