No. The sum of 1 odd number and 1 even number must always be odd.
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Yes --------------------------------------------- Let n be an integer. Then 2n is an even number Let m be an integer. Then 2m is an even number and 2m + 1 is an odd number. Then: even + odd = (2n) + (2m + 1) = (2n + 2m) + 1 = 2(n + m) + 1 = 2k + 1 (where k = m + n) which is an odd number.
Answer 2 Think about it. Assume that 1 is the odd number you are adding to an even number. Adding it will take you to the next number - which must be an odd number. If you add it to that number, it will take you to the next number, which now is an even number. If you use a number larger than 1 the principal is still the same.